[LeetCode] 175.Combine Two Tables 聯合兩表
Table: Person
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| PersonId | int |
| FirstName | varchar |
| LastName | varchar |
+-------------+---------+
PersonId is the primary key column for this table.
Table: Address
+-------------+---------+
| Column Name | Type |
+-------------+---------+
| AddressId | int |
| PersonId | int |
| City | varchar |
| State | varchar |
+-------------+---------+
AddressId is the primary key column for this table.
Write a SQL query for a report that provides the following information for each person in the Person table, regardless if there is an address for each of those people:
FirstName, LastName, City, State
LeetCode還出了是來到數據庫的題,來那么也來做做吧,這道題是第一道,相對來說比較簡單,是一道兩表聯合查找的問題,我們需要用到Join操作,關于一些Join操作可以看我之前的博客SQL Left Join, Right Join, Inner Join, and Natural Join 各種Join小結,最直接的方法就是用Left Join來做,根據PersonId這項來把兩個表聯合起來:
解法一:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person LEFT JOIN Address ON Person.PersonId = Address.PersonId;
在使用Left Join時,我們也可以使用關鍵Using來聲明我們相用哪個列名來進行聯合:
解法二:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person LEFT JOIN Address USING(PersonId);
或者我們可以加上Natural關鍵字,這樣我們就不用聲明具體的列,MySQL可以自行搜索相同的列:
解法三:
SELECT Person.FirstName, Person.LastName, Address.City, Address.State FROM Person NATURAL LEFT JOIN Address;
參考資料:
https://leetcode.com/discuss/21216/its-a-simple-question-of-left-join-my-solution-attached
https://leetcode.com/discuss/53001/comparative-solution-between-left-using-natural-left-join
到此這篇關于SQL實現LeetCode(175.聯合兩表)的文章就介紹到這了,更多相關SQL實現聯合兩表內容請搜索腳本之家以前的文章或繼續瀏覽下面的相關文章希望大家以后多多支持腳本之家!
您可能感興趣的文章:- SQL實現LeetCode(183.從未下單訂購的顧客)
- SQL實現LeetCode(182.重復的郵箱)
- SQL實現LeetCode(181.員工掙得比經理多)
- SQL實現LeetCode(180.連續的數字)
- SQL實現LeetCode(178.分數排行)
- SQL實現LeetCode(177.第N高薪水)
- SQL實現LeetCode(176.第二高薪水)
- SQL實現LeetCode(184.系里最高薪水)